60*(0.25-x)*(0.25-x)=4*x^2

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Solution for 60*(0.25-x)*(0.25-x)=4*x^2 equation: 



60(0.25-x)(0.25-x)=4x^2

We move all terms to the left:

60(0.25-x)(0.25-x)-(4x^2)=0

determiningTheFunctionDomain
-4x^2+60(0.25-x)(0.25-x)=0

We add all the numbers together, and all the variables

-4x^2+60(-1x+0.25)(-1x+0.25)=0

We multiply parentheses ..

-4x^2+60(+x^2-0.25x-0.25x+0.0625)=0

We multiply parentheses

-4x^2+60x^2+0x+0x+3.75=0

We add all the numbers together, and all the variables

56x^2+2x+3.75=0

a = 56; b = 2; c = +3.75;
Δ = b2-4ac
Δ = 22-4·56·3.75
Δ = -836
Delta is less than zero, so there is no solution for the equation

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